Part A: A mercury barometer ... Pick those that apply. a. has a column height th
ID: 2076340 • Letter: P
Question
Part A:
A mercury barometer ...
Pick those that apply.
a. has a column height that depends on the mass of atmospheric gas above it.
b. has a column height that depends on Earth's mass.
c. has a column height that depends on the pressure of the Earth's atmosphere.
d. has a column height that depends on Earth's radius.
Part B:
Atmospheric pressure on Earth at its surface is 101 KPa (101 kilopascals or 101,000 N/m2). Which of these statements is true.
a. If we pump out the gas in a closed container leaving only 1 billionth of the original gas, there will only be about 1000 atoms left in the container.
b. The number of atoms or molecules in the container does not depend on temperature.
c. If we pump out the gas in a closed container leaving only 1 millionth of the original gas there will still be more than 1013 (10,000 billion) atoms per cm3 in the container.
d. The number of atoms or molecules in the container depends on what the gas is composed of.
Part C:
In a gas that is a mixture of water (two H and one O) and carbon dioxide (one C and two O), if the water has average velocity of 308 m/s, what is the average velocity of the carbon dioxide molecule?
a. If we pump out the gas in a closed container leaving only 1 billionth of the original gas, there will only be about 1000 atoms left in the container.
b. The number of atoms or molecules in the container does not depend on temperature.
c. If we pump out the gas in a closed container leaving only 1 millionth of the original gas there will still be more than 1013 (10,000 billion) atoms per cm3 in the container.
d. The number of atoms or molecules in the container depends on what the gas is composed of.
Part C:
In a gas that is a mixture of water (two H and one O) and carbon dioxide (one C and two O), if the water has average velocity of 308 m/s, what is the average velocity of the carbon dioxide molecule?
Explanation / Answer
Part A) option c is correct
rho g h = Po
h = Po/(rho g).
Part B) n = PV/RT
Option d as it depends on T
Part C) v = v1*sqrt(M1/M2)
= 308* sqrt(18/44)
= 197 m/s