CSecure https//chip physics purdue edu/cgi-bin/241/surmmer2017/imnHomewok.om1750
ID: 2078418 • Letter: C
Question
CSecure https//chip physics purdue edu/cgi-bin/241/surmmer2017/imnHomewok.om17505/uiac 102-02-ct.cta2016 CHIP ID is:ebeach INTERACTIVE EXAMPLE Comment of E The left plate of a parallel plate capacitor carries a positive charge +Q, and the right plate carries a negative charge-O. The magnitude of the electric field between the plates in 100 kVm. The plates each have an area of 2 X 103 m2. The spacing between the plates is 6 X 103m. There is no dielectric between the plates Calculate the potential energy sored in the capacitor Enter 5) fer thet multiply credit by 0.3 up to 10 atempts LogoExplanation / Answer
energy density = e0 E^2 /2
= (8.854 x 10^-12) ( 100 x 10^3)^2 / 2
= 0.04427 J/m^3
volume = AL = (2 x 10^-3 m^2) (6 x 10^-3 m)
= 12 x 10^-6 m^3
Energy stored = energy density x volume
= 5.31 x 10^-7 J