Please answer each part fully for points. Show work, steps, etc. Five identical

Question

Please answer each part fully for points. Show work, steps, etc.

Five identical light bulbs are connected as shown. Each bulb has a fixed resistance of 4 ohms. (Note: Light bulbs carrying more current are brighter than light bulbs carrying less current.) Calculate the total resistance between the two terminals. For the following parts of this question, assume that a 12-volt battery has been connected to the two terminals. Which light bulb (or bulbs) will glow the dimmest? Calculate the current delivered by the 12-volt battery to the circuit. Calculate the current through light bulb D. Suppose light bulb B is unscrewed from its socket. Now calculate the current through light bulb D.

Explanation / Answer

a) Equivalent Resistance=4+4+4(8)/(4+8)=8+32/12=10.67

b) Least current will flow from B and C as total resistance in the branch connecting B and C is 8ohm whereas in branch D is 4 ohm. As we know that I=V/R. hence more the R less is the current. As A and E are in the main branch of circuit, they will be supplied with current which is equal to the sum of current supplied to B and C and the current supplied to D.

c) I=V/R

By (a), R=10.67ohm

ie I=12/10.67=1.125A

d) 1.125 A will be divided among branch having B and C and branch having D according to R

as resistance in branch with B and C is 8 and in branch with D is 4 hence 2/3 of I will flow by D and 1/3 will flow by B and C

ie I in C=2*I/3=2*1.125/3=0.750 A

e) When B is removed this branch becomes an open circuit hence all the current will flow from D and hence the current value is 1.125 A

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