Consider the human eye to be composed of a thin lens of uniform index of refract

Question

Consider the human eye to be composed of a thin lens of uniform index of refraction n = 1.45, with fluid of n = 1 inside, with the light-receptive cells a distance 24 mm from the lens. The eye can "focus" on different distances by changing the radius of curvature of its lens.

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Find the radius of curvature for this lens when you are looking at an object a distance of 59.5 mm from your eye's lens. (all incident light rays must still hit the light-receptive cells at the same distance as before)

Explanation / Answer

let the distance of the lens from the screen be x.so,

(1/(50-x))+(1/x)=1/10

or x=13.8197 cm and x=36.1803 cm

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