Consider the human eye to be composed of a thin lens of uniform index of refract

Question

Consider the human eye to be composed of a thin lens of uniform index of refraction n = 1.41, with fluid of n = 1 inside, with the light-receptive cells a distance 24 mm from the lens. The eye can "focus" on different distances by changing the radius of curvature of its lens.

Using figure 9.6 in your lab manual as a reference, find the radius of curvature for this lens when you are looking at very distant objects. (all incident light rays must hit the light-receptive cells at the same point)

answer in mm

Using figure 9.7 in your lab manual as a reference, find the radius of curvature for this lens when you are looking at an object a distance of 88.5 mm from your eye's lens. (all incident light rays must still hit the light-receptive cells at the same distance as before)

answer in mm

Explanation / Answer

First part, use f = R / (n-1)

f = focal distance (so 24 mm)

n = index of refraction of the lens (so 1.41)

so 24.5 = R / (1.41 - 1) --> R = 9.84

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