A slender rod with a length of 0.300m rotates with an angular speed of 8.80rad/s
ID: 2096251 • Letter: A
Question
A slender rod with a length of 0.300m rotates with an angular speed of 8.80rad/s about an axis through one end and perpendicular to the rod. The plane of rotation of the rod is perpendicular to a uniform magnetic field with a magnitude of 0.640T
A) What is the induced emf in the rod? E=?V
B) What is the potential difference between its ends? V=?V
C) Suppose instead the rod rotates at 8.80 rad/s about an axis through its center and perpendicular to the rod. In this case, what is the potential difference between the ends of the rod? V=?V
D) Suppose instead the rod rotates at 8.80 rad/s about an axis through its center and perpendicular to the rod. In this case, what is the potential difference between the center of the rod and one end? V=?V
Explanation / Answer
emf = integral 0 to L --- B v dr = integral 0 to L ----B *omega r dr,
=0.5 B omega L^2 = 0.25344 V