Consider a series LRC circuit with R = 98 Ohm , L = 0.39 H and C = 0.7 mu F. The

Question

Consider a series LRC circuit with R = 98 Ohm , L = 0.39 H and C = 0.7 mu F. The current is 6 mA amplitude at 0.8 kHz. Remember co = 2TTf, where f is the frequency in cycles per second or Hz. Find the angular resonant frequency of oscillations. Express the answer with one decimal place. Which of the phasor diagrams represents a series R-L-C circuit driven at resonance? A series ac circuit is shown. The inductor has a reactance of 100 Ohm and an inductance of 195 mH. A 97 Ohm resistor and a capacitor whose reactance is 127 Ohm, are also in the circuit. The rms current in the circuit is 1 A. In Figure, the phase angle (in degrees) of the circuit is:

Explanation / Answer

1)

resonant freqency = (1/(2*3.14))*1/sqrt(0.39*0.7*10^-6) = 304.76 Hz

So, angular frequency = 2*3.14*304.76 = 1913.9 rad/s <-----answer

2)QUESTION 2: answer : option 3

3)

phase angle = atan((100-127)/97) = -15.6 degrees

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