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Question

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A large positively-charged object with charge q+ = 4.25 mu C is brought near a negatively-charged plastic ball suspended from a string of negligible mass. The suspended ball has a charge of q_ = -52.3 nC and a mass of 12.5 grams. What is the angle the string makes with the vertical when the positively charged object is 19.5 cm from the suspended ball? The positively-charged object is at the same height as the suspended ball.

Explanation / Answer

F/mg = tan theta

9*10^9 * 4.25* 52.3 * 10^-15 / 0.038 = 0.0125*9.8*tan theta

theta = 23.25 degrees

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