In the famous TV program, Mythbusters, Adamand Jamie tested a waterslide. Please
ID: 2108449 • Letter: I
Question
In the famous TV program, Mythbusters, Adamand Jamie tested a waterslide. Please referto
below ‘Mythbusters waterslide’ in YouTube.
Part 1: http://www.youtube.com/watch?v=AMkW_vg6ygA
Part 2: http://www.youtube.com/watch?v=1T8xKGcmUuY
Part 3: http://www.youtube.com/watch?v=TGAnWgvl7SE
Part 4: http://www.youtube.com/watch?v=0OTrb_RwHz8Â
The geometry ofthe waterslide used in the TV show is(1m=3.28ft):
Slide length= 61m; Slope Angle=24degrees °; Ramp height=3.66m
The lubricantis used properly on the surface ofthe slide,therefore the friction isignored. Adam’s
weightis 70kg and he istreated as a particle. Adamstartssliding fromthe top.
Case 1: If Ramp angel=30Â °
 Using theoretical methods to determine: i) themagnitude and direction ofthe velocity
of Adamwhen he justflies away fromthe ramp; ii)the horizontal distance that Adam
flies.
Case 2:to change the ramp angle when keep other parameters unchanged:
 Using theoretical methodsto determine themagnitude ofthe ramp angle which will
resultin the max flying distance.
SORRY FOR THE PIC DIDN'T WANT TO SAVE THE ORIGINAL
Explanation / Answer
case 1) (i) height of the top ,h1= 61 sin24 = 24.8 m
using LCE , m g (h1-h2) = 0.5 m v^2 ====.> lvl = sqrrt(2 g (h1-h2) ) = 20.3 m/s......
vx = v cos 30 = 17.63 m/s..........
vy = v sin30 = 10.18 m/s..
angle = tan ^-1 (vy/vx) = 59.deg
)ii) range = v^2 sin(2*theta ) /g= v^2 sin(2*30) /g = 36.41 m
case2 ) to get range maximum v^2 sin(2*theta ) /g = max===>
sin(2*theta) = max ....
the max value of sin theta =1.....
sin 2 theta =1.
2 theta = 90deg...
theta = 45 deg.....