Refer to procedure 2. Assume the mass of the cart is m, and the mass hanging on
ID: 2121391 • Letter: R
Question
Refer to procedure 2. Assume the mass of the cart is m, and the mass hanging on the end of the string, M, is the maximum mass needed to just balance friction.
a) Suppose m = 2708 g and M = 885 g. Now, ?s, the coefficient of static friction between the cart and the surface, is
b) Suppose now that mass 796 g is added to m, the mass of the cart. Find the new mass M needed to keep the system at equilibrium.
g
c) Suppose the system is moved to the surface of the Moon, where the acceleration due to gravity is much less that that of Earth. Now:
1) The frictional force on the cart is decreased, and you would have to increase M to prevent the system from moving
2)The frictional force on the cart is increased, and you would have to increase M to prevent the system from moving
3) The frictional force on the cart is unchanged, and you would have to increase M to prevent the system from moving
4)The frictional force on the cart is decreased, and you would have to decrease M to prevent the system from moving
5)The frictional force on the cart is increased, and M is still the maximum mass needed to balance the system
6)The frictional force on the cart is increased, and you would have to decrease M to prevent the system from moving
7)The frictional force on the cart is unchanged, and M is still the maximum mass needed to balance the system
8)The frictional force on the cart is decreased, and M is still the maximum mass needed to balance the system
9)The frictional force on the cart is unchanged, and you would have to decrease M to prevent the system from moving
Need help with part C...I thought it was 7. but i was wrong
Explanation / Answer
A) The formula is force x coefficient of static friction=Force of friction.
So,
2.259 kg x 9.81 m/s^2 x %u03BCs = 0.850 kg x 9.81 m/s^2
Divide by 9.81 m/s^2
2.259 kg x %u03BCs = 0.850 kg
Divide by 2.259 kg
%u03BCs = 0.376
B) Same, but you already know %u03BCs.
(2.259 kg + 0.549 kg) x 9.81 m/s^2 x 0.376 = M x 9.81 m/s^2
Divide by 9.81 m/s^2
2.808 kg x 0.376 = M
1.056 kg = 1056 g = M