Please explain how to get each answer. They are all correct. Thank you! 9. (12 p
ID: 212187 • Letter: P
Question
Please explain how to get each answer. They are all correct. Thank you!
9. (12 points) Below is the mRNA and protein sequence for an imaginary gene. For this gene to have activity, the ArgGly Ala sequence at the C terminus of the protein must be expressed 5 UUAUGUCUACUUUAGUUCCUCAUCGUGGGGCAUAGUAC3" A. On the mRNA sequence above circle the bases that encode the Arg-Gly-Ala sequence. (3 points) B. How many amino acids long is the Gene X protein? 10 (3 points) For each, predict whether the mutation(s) will: You isolated two mutations in this gene, mutant #1 has a single mutation and mutant #2 allele is a double mutation. Their mRNA sequences are indicated below (the mutated base is in bold and C. Mutant #1 : 5, UUAUGUCUACUUAAGUUCCUCAUCGUGGGGCAUAGUAC3. Mutant #1 will (circle only one): (3 points) A. Destroy the activity of the gene B. Have no effect on the activity of the gene C. Unable to predict. D. Mutant #2: 5,UUAUGUCUACUUUAGUUCCCCAUCGUGGAGCAUAGUAC3 Mutant #1 will (circle only one): (3 points) A. Destroy the activity of the gene B. Have no effect on the activity of the gene C. Unable to predictExplanation / Answer
Imaginary mRNA: 5’ UU AUG UCU ACU UUA GUU CCU CAU CGU GGG GCA UAG UAC 3’
A.)
5’ UU AUG UCU ACU UUA GUU CCU CAU CGU GGG GCA UAG UAC 3’
AUG – Start codon.
UAG – Stop codon.
CGU GGG GCA – Arginine Glycine Alanine
Translation begin from start codon which codes for methionine.
Translation terminates at stop codon.
B.)
5’ UU AUG UCU ACU UUA GUU CCU CAU CGU GGG GCA UAG UAC 3’
Met Ser Thr Leu Val Pro His Arg Gly Ala Stop
Total Amino Acid # - 10
C.)
5’ UU AUG UCU ACU UAA GUU CCU CAU CGU GGG GCA UAG UAC 3’
Met Ser Thr Stop
UAA – Stop codon.
Hence it destroys the activity of the gene.
D.)
5’ UU AUG UCU ACU UUA GUU CCC CAU CGU GGA GCA UAG UAC 3’
Met Ser Thr Leu Val Pro His Arg Gly Ala Stop
CCU, CCC, CCA, CCG – Proline.
GGU, GGC, GGA, GGG – Glycine.
It’s a synonymous mutation. All these codon codes for the same amino acid. Hence no effect in the functionality of the protein.