Consider an L-R circuit as shown in the figure. The battery provides 12.0V of vo

Question

Consider an L-R circuit as shown in the figure. The battery provides 12.0V of voltage. The inductor has inductance L, and the resistor has resistance R = 150ft . The switch is initially open as shown. At time t = 0, the switch is closed. At time t after t = 0 the current I(t) flows through the circuit as indicated in the figure. What is the current reading 7(r) given by the ammeter shown in the circuit at one time constant after t = 0? Express your answer in amperes. What is the current I(3tau) at a time after t = 0 equal to three times the time constant? Express your answer in amperes.

Explanation / Answer

i = (12/150 )(1-e^-3) = 7.6*10^-2 A

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