Part 1. A parcel of fluid is raised from the middle of layer 2 to 30 meters abov
ID: 2125081 • Letter: P
Question
Part 1. A parcel of fluid is raised from the middle of layer 2 to 30 meters
above the interface between layers 1 and 2, and then released. (Each layer is 50 m thick)
layer 1, density = 1022
layer 2 density = 1026
layer 3 density = 1029
layer 1, density = 1022
layer 2 density = 1026
layer 3 density = 1029
Explanation / Answer
assuming that the parcel is intially stable,
it's density=1025 kg/m^3
so force on it in layer 1=p1*V*g
so acceleration= 9.8+(1022*1026)*9.8
so speed=2as
=19.56 ms^-2
so speed=2*19.56*30
=1173.56 m/s