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After you pick up a spare, your bowling ball rolls without slipping back toward

ID: 2127288 • Letter: A

Question

After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3.42 m/s (Figure 10-24). To reach the rack, the ball rolls up a ramp that gives the ball a h = 0.46 m vertical rise. What is the speed of the ball when it reaches the top of the ramp?style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">color="red">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">style="font-family: verdana, helvetica, sans-serif; font-size: 13px; line-height: 20px;">


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After you pick up a spare, your bowling ball rolls without slipping back toward the ball rack with a linear speed of v = 3.42 m/s (Figure 10-24). To reach the rack, the ball rolls up a ramp that gives the ball a h = 0.46 m vertical rise. What is the speed of the ball when it reaches the top of the ramp?

Explanation / Answer

Vf = sqrt (vi^2 - 10/7gy)


= sqrt (3.42^2 - 10/7 * 9.8 *0.46)

= 2.29 m/s