Please Answer the following questions!!!!! A small glass bead has been charged t
ID: 2129534 • Letter: P
Question
Please Answer the following questions!!!!!
A small glass bead has been charged to 6.8 nC. What is the magnitude of the electric field 2.0 cm from the center of the bead? (k = 1/4piepsilon0 = 8.99 times 109 N · m2/C2) (answer in N/C) A proton is placed in an electric field of intensity 800 N/C. What are the magnitude and direction of the acceleration of this proton due to this field? (m proton = 1.67 times 10-27 kg, e = 1.60 times 10-19 C) (answer in m/s^2) An electric field is set up between two parallel plates, each of area 2.0 m2, by putting 1.0 muC of charge on one plate and -1.0 muC of charge on the other. The plates are separated by 4.0 mm with their centers opposite each other, and the charges are distributed uniformly over the surface of the plates. What is the magnitude of the electric field between the plates at a distance of 1.0 mm from the positive plate, but not near the edges of the plates? [epsilon0=8.85times10-12 C2/N · m2]Explanation / Answer
4. E = Kq/r^2 = 8.99 x 109 x 6.8 x 10-9 / 0.02^2 = 152830 N/C
5. a = F/m =qE/m = 7.66 x 10^10 m/s2
direction same of field direction
6. E = qd/e0A = 1 x 10-6 x 4 x 10-3 / 8.854 x 10-12 x2 = 225.89 N/C