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Three forces of magnitudes F 1 = 4.0 N , F 2 = 6.0 N , and F 3 = 8.0 N are appli

ID: 2133076 • Letter: T

Question

Three forces of magnitudes F1=4.0N, F2=6.0N, and F3=8.0N are applied to a block of mass m=2.0kg, initially at rest, at angles shown on the diagram. (Figure 1) In this problem, you will determine the resultant (net) force by combining the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive).

A)

Three forces of magnitudes F1=4.0N, F2=6.0N, and F3=8.0N are applied to a block of mass m=2.0kg, initially at rest, at angles shown on the diagram. (Figure 1) In this problem, you will determine the resultant (net) force by combining the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive). Calculate the magnitude of the resultant force F? r=F? 1+F? 2+F? 3 acting on the block. Express the magnitude of the resultant force in newtons to two significant figures.

Explanation / Answer

Answer question



Fnetx = 4*cos25+6*cos325+8*cos180= 0.540 N

Fnet y = 4*sin25+6*sin325+8*sin180 = ?1.751 N

A) magnitude = 1.83 N

B) angle = 287.14

C) a = Fnet /m =0.915m/s^2
D )angle = 287.14

E) S = 0.5*a*t^2 = 11.44m