In the figure are shown three capacitors with capacitances C 1 = 6.00 ? F , C 2

Question

In the figure are shown three capacitors with capacitances C1=6.00?F,C2=3.00?F,C3=5.00?F. The capacitor network is connected to an applied potential Vab. After the charges on the capacitors have reached their final values, the charge Q2 on the second capacitor is 40.0 ?C.

What is the charge Q1 on capacitor C1?

What is the charge on capacitor C3?

What is the applied voltage, Vab?

In the figure are shown three capacitors with capacitances The capacitor network is connected to an applied potential After the charges on the capacitors have reached their final values, the charge Q2 on the second capacitor is What is the charge Q1 on capacitor C1? What is the charge on capacitor C3? What is the applied voltage, Vab?

Explanation / Answer

Charge on C2 = 40 ?C
Voltage across C2 = charge on C2 / capacitance
= 40?C / 3?F = 16.67 V

C1 and C2 are in parallel. Hence, same voltage exists across C1 and C2. In that case charge on a capacitor is directly proportional to their capacitance.
So, charge on C1 = (40 ?C) x (6?F / 3?F) = 80?C

Total charge on C1 and C2 = 40?C + 80?C = 120?C.
Since C3 is in series with the combination of C1 and C2, charge on C3 = 120?C

Voltage across C3 = 120?C / 5?F = 24 V

Vab = sum of voltages across C1 & C2 combination and C3
Vab = 16.67 + 24 = 40.67 V

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