The diagram below shows a battery of voltage V connected to two cylindrical wire
ID: 2152201 • Letter: T
Question
The diagram below shows a battery of voltage V connected to two cylindrical wires. Both wires are made out of the same material and are of the same length, however the diameter of wire A is twice the diameter of wire B Choose the correct answer. The voltage drop across wire B is 1/16 the voltage drop across wire A. The voltage drop across wire B is half the voltage drop across wire A. The voltage drop across wire B is one fifth the voltage drop across wire A. The voltage drop across wire B is five times the voltage drop across wire A. The voltage drop across wire B is twice the the voltage drop across wire A. The voltage drop across wire B is one quarter the voltage drop across wire A. The voltage drop across wire B is four times the voltage drop across wire A. The voltage drop across wire B is equal to the voltage drop across wire A. The voltage drop across wire B is sixteen times the voltage drop across wire A. Choose the correct answer. The power dissipated in wire B is one fifth times the power dissipated in wire A The power dissipated in wire B is 1/16 times the power dissipated in wire A The power dissipated in wire B is five times the power dissipated in wire A The power dissipated in wire B is sixteen times the power dissipated in wire A. The power dissipated in wire B is half the power dissipated in wire A. The power dissipated in wire B is one quarter the power dissipated in wire A. The power dissipated in wire B is twice the power dissipated in wire A. The power dissipated in wire B is four times the power dissipated in wire A. The power dissipated in wire B is sixteen times the power dissipated in wire A
Explanation / Answer
R = L/A
V = iR
Va = Vb / 4
The voltage drop across wire B is four times the voltage drop across wire A
P = i2R
Pa = Pb / 4
The power dissipated in wire B is four times the power dissipated in wire A