A 50g steel ball moving on a frictionless horizontal surface at 2.0 m/s^1 hits a

Question

A 50g steel ball moving on a frictionless horizontal surface at 2.0 m/s^1 hits a stationary 20g ceramic ball. After the collision the ceramic ball moves off at a velocity of 2.5 m/s^-1
(i) Calculate the velocity of the steel ball after the collision. (remember that the total momentum of the system is conserved in the collision)
(ii) Calculate the total kinetic energy of the balls before the collision and again after the collision.
(iii) From your results in part (ii) has kinetic energy been conserved. If not, where has this energy gone

Explanation / Answer

i)50*10-3*2=50*10-3*v+20*10-3*2.5
v=1m/s

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