If F1 stands for a force vector of magnitude 30.0 N and F2 stands for a force ve

Question

If F1 stands for a force vector of magnitude 30.0 N and F2 stands for a force vector of magnitude 40.0N acting in the directions shown, what is the equilibrant force that would be needed to compensate for the resultant force of the vectors F1 and F2 that was calculated?

The resultant forces: magnitude = 60.83 N and the direction wrt the x axis = 34.71 degrees

I don't know how to calculate the equilibrant force needed, please help! :)

(I have another question I'm confused on about this problem: http://www.chegg.com/homework-help/questions-and-answers/question-q2898012)

Explanation / Answer

resultant of F1 and F2 =(F12 + F22 +2F1*F2*cos)

=(30*30+40*40+2*30*40*cos60) = 60.827 N

angle of resultant will be tan-1(F2*cos/(F1+F2*sin))=34.71

Vector required to compensate the effect of resultant of 2 Forces will be the Force equal in magnitude but opposite in direction

So angle between Resultant and required force vector=180

If resultant vector makes 34.71 degree with X axis

then required force vector makes angle 34.71+180 with X axis = 214.71 with +X axis

which can be also written as 360-214.71 = -145.30 degrees with +X axis

Both values can be written

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