If F= 680 lb, determine the components of the force acting parallel to the axis

Question

If F= 680 lb, determine the components of the force acting parallel to the axis of the pole Fundamental Problem 2.30 Fundamental Problem 2.30 Part A F 680 1b, determine the components of the force acting peralel to the axis of the pole Elaure.1) Determine (Fa) Express your answer to three significant figures and include the appropriate units HA Fa) Value Units Submit My Answers Give Up Incorrect; Try Again; 4 attempts remaining Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of signiicant tg Part B Determine (A) Express your answer to three significant figures and include the appropriate units. (FA)Value Units Submit My Answers Cive Up

Explanation / Answer

PartA) Fy =F cos 60 degree *cos 30 degree = 680*0.5*0.866

= 294.44 lb

Fx = - F cos 60 degree sin 30 degree = 680*0.5*0.5

= 170 lb

Fz = F sin 60 degree =680* 0.866 = 588.88 lb

Component parallel to axis

= (294.44*4+-170*-4 + 588.88*2)/sqrt (4^2 +4^2 +2^2)

= 506 lb

Part b) perpendicular component = sqrt (680^2 - 506^2)

= 454 lb

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