In the Challenger Deep of the Marianas Trench, the depth of seawater is 10.9 km
ID: 2177565 • Letter: I
Question
In the Challenger Deep of the Marianas Trench, the depth of seawater is 10.9 km and the pressure is 1.16 * 10^{8} Pa (about 1.15 *10^{3} atm).If a cubic meter of water is taken from the surface to this depth, what is the change in its volume? (Normal atmospheric pressure is about 1.0 *10^{5} Pa . Assume that k for seawater is 45.8 *10^{-11}Pa^{-1}.)______m^3
What is the density of seawater at this depth? (At the surface, seawater has a density of 1.03*10^{3}kg/m^{3}.) _____kg/m^3
Please show work!
Thanks!
Explanation / Answer
1/k=p*V/dv a)so dv=p*k [V=1] =.053 b)d=1030*(V-dv)/V=975.41 g/cc