I just need the second part numbers 1-6 This problem is the continuation of the

Question

I just need the second part numbers 1-6

This problem is the continuation of the previous problem. At the bottom of the hill is Molly's identical twin sister, Dolly. Dolly is at rest. When Molly collides with Dolly, they hug and do not let go. Answer the following: Is this an inelastic or an elastic collision? Why? What is conserved in this collision? What is not conserved in this collision? What is the velocity of the twins immediately after the collision? What is the total kinetic energy before the collision? What is the total kinetic energy after the collision? Are your answers for parts 4 and 5 different? Should they be different? If they are different, where did the energy go? If you did not get an answer for velocity from the previous problem, use 200m/s.

Explanation / Answer

1. It is an inelastic collision, as both bodies have the same velocity after collision.

2. Momentum is conserved here, kinetic energy is not conserved.

3. conserving the momentum,

mvi =2mvf

as vi =200 m/s, vf=100 m/s

4. Total KE before collision=(1/2)m*2002=20000m

5. Total KE after collision= (1/2)(2m)*1002=10000m

6. The answers to parts 4 and 5 should be different, as some energy goes in the inelastic deformation of the bodies to make them a single body.

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