Consider the depicted circuit. The voltage source is a 5 V power supply. The sol
ID: 2183711 • Letter: C
Question
Consider the depicted circuit. The voltage source is a 5 V power supply. The solenoid is considered to be ideal so that it has no internal resistance. Both resistors are the same: 5.0 Ohm. Assume the switch had been closed for a long time. Use Kirchhoff's rules to determine the voltage drop across R2. V2 = At the instant just after the switch was opened, what is the current though the solenoid? At the instant just after the switch was opened, what is the current though R2? At the instant just after the switch was opened, what the current though R1? At the instant just after the switch was opened, what the magnitude of the voltage drop across R1? Suppose R1 were replaced with a 5 M Ohm resistor and the switch had been closed for a long time. What would the magnitude of the voltage drop across R1 be just after the instant in which the switch was opened?Explanation / Answer
by applying krichoff's law v = iR1 + iR2 + iL where is L is solenoid so v across r2 is v = v2 + vL since RL is 0 so VL = iL * RL so VL = 0 so V2 = V when switch is opened v = iR1 + iR2 + iL since i is same as series cct. so iR1 = iR2 = iL iL = v - iR1 - iR2 i1 will be equal to i2 v1 = i1 * R1