In the second part of the experiment, the latent heat of vaporization for water
ID: 2201374 • Letter: I
Question
In the second part of the experiment, the latent heat of vaporization for water is measured. In this experiment, water, steam, the inner aluminum can, and the aluminum stirrer gain or lose heat energy. There are three temperatures involved: 100oC, Ti (the starting temperature of the water in the calorimeter), and Tf (the final temperature of the water in the calorimeter). Equation 8 can be rewritten [msteamLv] + [msteamcw(100oC - Tf)] = [mwcw(Tf - Ti)] + [Ccst(Tf - Ti)] Each of the four terms in brackets represents an energy. For each term explain which substance. You must answer all portions of this question correctly to receive credit. A. Water condensed from steam B. Steam C. Water in calorimeter D. Calorimeter can and stirrerExplanation / Answer
the terms in brackets are numbered from left. first term is B as steam can only change state.it is at 100 C and converts to water at 100 C. [energy released] second term is A . because it is going from 100 to Tf. [energy released] third term is C . it is going from Ti to Tf. [energy absorbed] fourth term is D. it is also going from Ti to Tf. [energy absorbed]