The diagram below shows a block of mass 2.85 , on a frictionless horizontal surf
ID: 2218716 • Letter: T
Question
The diagram below shows a block of mass 2.85 , on a frictionless horizontal surface, as seen from above. Three forces of magnitudes = 7.68 , = 4.8 , and = 9.27 , are applied to the block, initially at rest on the surface, at angles shown on the diagram. (Figure 1) In this problem, you will determine the resultant (total) force vector from the combination of the three individual force vectors. All angles should be measured counterclockwise from the positive x axis (i.e., all angles are positive). 1.Calculate the magnitude of the total resultant force acting on the mass. 2.What angle does make with the positive x axis? 3.What is the magnitude of the mass's acceleration vector, ? 4.What is the direction of ? In other words, what angle does this vector make with respect to the positive x axis? 5.How far (in meters) will the mass move in 5.0 s? 6.What is the magnitude of the velocity vector of the block at ? 7.In what direction is the mass moving at time ? That is, what angle does the velocity vector make with respect to the positive x axis? fig
Explanation / Answer
F_x=7.68*cos25+4.7*cos35-9.27=1.54
F_y=7.68*sin25-4.7*sin35=0.55
net = 1.635
b) tan=0.55/1.54=> =19.65 from x axis
c)a=F/m=0.573
d)direction is same as that of the force at the same angle
e) disatnce = 0.5aT^2=10.314 m