Coulomb\'s law for the magnitude of the force F between two particles with charg
ID: 2220227 • Letter: C
Question
Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is where K = , and = 8.854 times 10-12 C2/(N m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -15.5nC , is located at x1 = -1.690m ; the second charge, q2 = 33.0nC »is at the origin (x = 0.0000). What is the net force exerted by these two charges on a third charge q3 = 53.5nC placed between q1 and q2 at x3 = -1.125m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.Explanation / Answer
F = -kq3 (q1/r1^2 + q2/r2^2) = 9e9*53.5e-9*(19.5e-9/(1.675-1.145)/(1.675-1.145) + 38e-9/(1.145*1.145)) = 4.74E-5 N