Coulomb\'s law for the magnitude of the force F between two particles with charg

Question

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is |F| = K|QQ'| / d2, where K = 1 / 4 pi epsilon 0, and epsilon 0 = 8.854 times 10-12 C2 / (N middot m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -15.0nC, is located at x1 = -1.650m ; the second charge. q2 = 33.0nC, is at the origin (x = 0.0000). What is the net force exerted by these two charges on a third charge q3 = 46.5nC placed between q1 and q2 at x3 = -1.190m ? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures.

Explanation / Answer

first thing .. image is not opening second.. where do you want the force? please clarify and rate the answer :)

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