Consider the situation below, where the circle represents an ideal frictionless
ID: 2233227 • Letter: C
Question
Consider the situation below, where the circle represents an ideal frictionless pulley. The incline is frictionless; the block on the horizontal surface has a coefficient of static friction of 0.30 and a coefficient of kinetic friction of 0.15. Assume the blocks are initially at rest. Draw free body diagrams for each block. If theta = 15degree will the system start accelerating? When you plug numbers into your equations, it should agree with the fact that when theta = 45degree the system will accelerate. What will that acceleration be?Explanation / Answer
(b): F2 = m2 g sin15 = 40*9.8*0.25882 = 101.46 N ********* F1 = us m1 g = 0.3*25*9.8 = 73.5 N -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- ====> F2 > F1 =====> The system will start accelerating. -------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- (c): a = (F2 - F1)/(m1+m2) = (m2 g sin45 - us m1 g)/(m1+m2) = (40*9.8*0.7071-0.15*25*9.8 )/(40+25) = 3.70 m/s2