Charge q1= 1.80 times 10-8 C is placed at the origin O. Charge q2 = -7.20times10
ID: 2235164 • Letter: C
Question
Charge q1= 1.80 times 10-8 C is placed at the origin O. Charge q2 = -7.20times10-8C is placed at point A (0.18 m, 0 m) as shown in the figures. A charge q3 = 2.5 times 10-8 C is placed at point B (0.090 m,0) as shown in fig.a. Determine the net force F rightarrow 3 exerted on charge q3 by q1 and q2 The charge q3 is now placed at point C (0.27 m,0) as shown in fig.b. Determine the net force F rightarrow 3 exerted on charge q3 by q1 and q2. Find the coordinate x of a point D on the negative x-axis for which of the net force F rightarrow 3, exerted on q3, by q2 and q1 is zero. Use fig.c.Explanation / Answer
Force on the Charge q3 = kq1/r^2 + kq2/r'^2
= (9*10^9*1.80*10^-8)/(0.090^2) + (9*10^9*7.20*10^-8)/(0.18-0.09)^2
= 1*10^5 N