Mercury is poured into a U-tube as shown in Figure (a). The left arm of the tube

Question

Mercury is poured into a U-tube as shown in Figure (a). The left arm of the tube has cross-sectional area A1 of 10.8 cm2, and the right arm has a cross-sectional area A2of 4.50 cm2. Two hundredgrams of water are then poured into the right arm as shown in Figure (b).

Mercury is poured into a U-tube as shown in Figure (a). The left arm of the tube has cross-sectional area A1 of 10.8 cm2, and the right arm has a cross-sectional area A2of 4.50 cm2. Two hundredgrams of water are then poured into the right arm as shown in Figure (b). Determine the length of the water column in the right arm of the U-tube. cm Given that the density of mercury is 13.6 g/cm3, what distance h does the mercury rise in the left arm? cm

Explanation / Answer

Volume of waterpoured =mass/density=200/1=200cc

Area of right limb =4.5cm^2

height of water column=200/4.5=44.44cm

b)h*A1 =MASS OF MERCURY DISPLACED= h0*A2

Finally,

(h+h0)*13.6=1* 44.44

h+2.4h=44.44/13.6,h=.961cm

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