I would really appreciated if you answered in a piece of paper and took a pictur

Question

I would really appreciated if you answered in a piece of paper and took a picture and uploaded or wrote the answer in a very clear format. As well write as much possible details. Thanks so much!

To determine the specific heat capacity of lead, you heat 500g of lead shot to 100 degree C and place it in an aluminum calorimeter of mass 250g. that contains 500g of water initially at 17.5 degree C. If the final temperature of the mixture is 21.5 degree C, what is the specific heat of lead? (take specific heat of water to be 4186 J/kg.K and specific heat of aluminum to be 900 J/kg.K)

Explanation / Answer

using energy conservation,

0.500x c x (100-21.5) = 0.250 x 900 x (21.5 - 17.5) + 0.500 x 4186 x (21.5 - 17.5)

c = 236.23 J/Kg K

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