In the circuit shown, E = 1.2 kV, C = 6.5uF and R1 = R2 = R3 = R = 0.73 M ? With

Question

In the circuit shown, E = 1.2 kV, C = 6.5uF and

R1 = R2 = R3 = R = 0.73 M?

With C completely uncharged, switch S is suddenly closed (at t = 0).

a) For t = 0, which is i1 on the resistor R1.

b) The current i2 in the resistor R2.

c) The current i3 in resistor R3.

d) For t = infinity , which is the value of i1, i2 and i3.

In the circuit shown, E = 1.2 kV, C = 6.5uF and R1 = R2 = R3 = R = 0.73 M? With C completely uncharged, switch S is suddenly closed (at t = 0). For t = 0, which is i1 on the resistor R1. The current i2 in the resistor R2. The current i3 in resistor R3. For t = infinity , which is the value of i1, i2 and i3.

Explanation / Answer

At time t=0,

the capacitor does not provide any resistance to the flow of current.

let i1 (throgh R1), i2(through R2) and i3 through R3

i1 = i2 + i3

and applying KVL,

-E+ i1.R1+ i2.R2=0

also, i2. R2 - i3 R3=0

solving,

a . i1 = 1.2Kv/(0.73 + 0.73/2) = 1.096 mA

b. i2 = i1/2 = 1.096 mA / 2 = 0.548 mA

c. i3 = i1/2 = 1.096 mA / 2 = 0.548 mA   

d. t= infinity, capacitor work as open circuit

i3 =0 , i1= i2 = 1.2Kv /(0.73*2) = 0.822 mA

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