In the figure below, two 7.40 kg blocks are connected by a massless string over

Question

In the figure below, two 7.40 kg blocks are connected by a massless string over a pulley of radius 2.00 cm and rotational inertia 9.40 times 10-4 kg m2. The string does not slip on the pulley; it is not known whether there is friction between the table and the sliding block; the pulley's axis is frictionless. When this system is released from rest, the pulley turns through 0.70 rad in 77.0 ms, and the acceleration of the blocks is constant. What is the magnitude of the pulley's angular acceleration? What is the magnitude of either block's acceleration? What is the string tension T1? What is the string tension T2?

Explanation / Answer

a)theta=0.5*angular acceleration*t^2

so angular acceleration=236.127 rad/sec^2

b)so acceleration of the system=angular acceleration*radius=4.722 m/s^2

c)balancing force on block connected to T1,

7.4*9.8-T1=7.4*4.722

T1=37.573 N

d) (T1-T2)*radius=moment of inertia*angular acceleration

so T2=26.475 N

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