Please solve 3 & 4 A conducting rod moving perpendicularly to a magnetic field w

Question

Please solve 3 & 4

A conducting rod moving perpendicularly to a magnetic field will have a voltage produced between the two ends due to the magnetic force on the electrons being equal to the electrical force inside the wire due to the voltage difference. Suppose a 3 m conductor is moving at 70 miles/hr perpendicularly to a field of 0.5 times 10-4 T. What is the voltage between the ends of the rod? What is the electic field inside the rod? Suppose there is a resistor of l.5 times 106 Ohms in series with a 1.5 H inductor and a 12 volt battery and a switch. What is the voltage across the inductor one microsec after the switch is closed?

Explanation / Answer

3)

V=70 miles/hour

1mile/hour =0.44704 m/s

V=70*0.44704 =31.3 m/s

e=BLV =0.5*10^-4*3*31.3

e=4.694*10^-3 V or 4.694 mV

b)

E=V/L =4.694*10^-3/3

E=1.56*10^-3 V/m or 1.56 mV/m

4)

T=L/R =1.5/(1.5*10^6)=1*10^-6 s

V=Vo[1-e^(-t/T)]

V=12[1-e^(-1*10^-6/1*10^-6)]

V=7.585 V

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