Part 1: An inductor with L = 9.15 m H is connected across an ac source that has

Question

Part 1:

An inductor with L = 9.15mH is connected across an ac source that has voltage amplitude 45.5V .

the phase angle ? for the source voltage relative to the current: 90 deg

What value for the frequency of the source results in a current amplitude of 4.50A ?

Part 2:

An L-R-C series circuit is connected to a120?Hz ac source that has vrms = 79.0V . The circuit has a resistance of 76.0? and an impedance at this frequency of 110? .

A. What average power is delivered to the circuit by the source? (W)

Explanation / Answer

I = V/Z = 45.5/(2*pi*f*9.15E-3) = 4.5

f=175.9 Hz

2) P = I rms Vrms cos phi = Vrms^2/Z ( R/Z) = 79^2*76/110^2= 39.2 W

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