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A small 3.00 k g brick is released from rest 3.00 m above a horizontal seesaw on

ID: 2257615 • Letter: A

Question

A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s SubmitMy AnswersGive Up Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s SubmitMy AnswersGive Up Provide FeedbackContinue Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s SubmitMy AnswersGive Up Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s SubmitMy AnswersGive Up Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s SubmitMy AnswersGive Up Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s SubmitMy AnswersGive Up Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s SubmitMy AnswersGive Up Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s SubmitMy AnswersGive Up Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s SubmitMy AnswersGive Up Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s SubmitMy AnswersGive Up L = kg?m2/s L = kg?m2/s SubmitMy AnswersGive Up Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s SubmitMy AnswersGive Up Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s SubmitMy AnswersGive Up L = kg?m2/s L = kg?m2/s SubmitMy AnswersGive Up Provide FeedbackContinue Figure 1 of 1 L = kg?m2/s A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw.

Explanation / Answer

Required angular momentum

= m * v * (perpendicualr distance)

= 3 * 0 * 1.6

= 0 kgm/s


(b) At the instant it hits:

v^2 = u^2 + 2as

v^2 = 0 + 2*9.81*3 = 58.86

Thus, v = 7.67 m/s

Angular momentum = 3 * 7.67 * 1.6 = 36.83 kg.m/s