A small 3.00 k g brick is released from rest 3.00 m above a horizontal seesaw on
ID: 2257615 • Letter: A
Question
A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s Provide FeedbackContinue Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s Part A Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. L = kg?m2/s L = kg?m2/s L = kg?m2/s Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s Part B Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw. L = kg?m2/s L = kg?m2/s L = kg?m2/s Provide FeedbackContinue Figure 1 of 1 L = kg?m2/s A small 3.00kg brick is released from rest 3.00m above a horizontal seesaw on a fulcrum at its center, as shown in the figure below (Figure 1). Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant the brick is released. Find the angular momentum of this brick about a horizontal axis through the fulcrum and perpendicular to the plane of the figure the instant before it strikes the seesaw.Explanation / Answer
Required angular momentum
= m * v * (perpendicualr distance)
= 3 * 0 * 1.6
= 0 kgm/s
(b) At the instant it hits:
v^2 = u^2 + 2as
v^2 = 0 + 2*9.81*3 = 58.86
Thus, v = 7.67 m/s
Angular momentum = 3 * 7.67 * 1.6 = 36.83 kg.m/s