Can you help me for answering my lab questions: 1- you took datawith the PVC cyl
ID: 2257917 • Letter: C
Question
Can you help me for answering my lab questions:
1- you took datawith the PVC cylinder at an angle near 8 degrees. if instead, you had taken data at an angle near 12 degrees. would the magnitued of the acceleration of the cylindernwhen moving up the incline had been larger, smaller or the same? what about when it was moving down the incline? Explain both answers.
2- When the cylinder was sliding on the track at an angle near 8 degrees, which of the following has a larger magnitude: the kinetic friction force or the parallel component of the wight force acting on the cylinder? Explain how you can tell without making any calculation at all/
3- Why does the acceleration of the cart going up and down the incline only look significantly different at very small angle of inclination?
here are the lab description:
http://postimg.org/gallery/2s608zpi/
and here is my data table in case:
http://postimg.org/image/5bqv2khyz/
thanks
Can you help me for answering my lab questions: you took datawith the PVC cylinder at an angle near 8 degrees. if instead, you had taken data at an angle near 12 degrees. would the magnitued of the acceleration of the cylindernwhen moving up the incline had been larger, smaller or the same? what about when it was moving down the incline? Explain both answers. When the cylinder was sliding on the track at an angle near 8 degrees, which of the following has a larger magnitude: the kinetic friction force or the parallel component of the wight force acting on the cylinder? Explain how you can tell without making any calculation at all/ Why does the acceleration of the cart going up and down the incline only look significantly different at very small angle of inclination?Explanation / Answer
A)accelaration a=g sin?
1) moving up the plane
here mg is resolved into two components......one component is opposite to the Normal force and other component is parallel to the inclined plane..........
A) when it was moving upwards.....
N=mg cos? and cancel each other....
Fnet=mg sin?.........
according to newton's second law...
Fnet=ma=mg sin?....
a= g sin?.....as the body moves up the plane the accelaration is opposite to the direction of motion....
a=-g sin?....when theta=8 degrees...
a=-g sin8=-1.363 m/s^2.....
when theta=12 degrees....
a=-gsin(12)=-2.03 m/s^2......
moving up the plane the magnitude of accelaration decreses...
moving down the plane
N=mg cos? and cancel each other....
Fnet=mg sin?.........
according to newton's second law...
Fnet=ma=mg sin?....
a= g sin?.....as the body moves up the plane the accelaration is in the direction of motion....
a=g sin?....when theta=8 degrees...
a=g sin8=1.363 m/s^2.....
when theta=12 degrees....
a=gsin(12)=2.03 m/s^2......
moving down the plane the accelarration increases
2) when it was sliding down......
Fnet=mg sin?-fk.....
the parallel component of the wight force acting on the cylinder is larger
when it was sliding up the plane.....
Fnet=fk+mg sin?........
the parallel component of the wight force acting on the cylinder is larger so that is why the body was sliding
3) going up the plane......
a=g[ sin?+uk cos?]......(1)
going down the plane.....
a=g[ sin?-uk cos?].....(2)
in the above equations accelaration depends upon the angle of inclination.......
however smaller is the angle accelartion significanly changes from those two equations...
the acceleration of the cart going up and down the incline only look significantly different at very small angle of inclination