In the circuit shown in the figure below, R = 5.0 ? , ? 1 = 12.0 V and ? 2 = 8.0
ID: 2258887 • Letter: I
Question
In the circuit shown in the figure below, R = 5.0 ?, ?1 = 12.0 V and ?2 = 8.0 V.
In the circuit shown in the figure below, R = 5.0 ?, ?1 = 12.0 V and ?2 = 8.0 V. Find the current through the 5.0 ? resistor. Find the total rate of dissipation of electrical energy in the 5.0 ? resistor and in the internal resistance of the batteries. In one of the batteries, chemical energy is being converted into electrical energy. In which one is this happening? In one of the batteries, electrical energy is being converted into chemical energy. In which one is this happening? Show that the overall rate of production of electrical energy equals the overall rate of consumption of electrical energy in the circuit.Explanation / Answer
a)
current = V/R = (12-8)/(5+1+1) = 0.571 A
b)
P1 = R I^2 = 0.571^2*5 = 1.63 W
P2 = r i^2 = 0.571^2*1 = 0.32653 W
P3 = r i^2 = 0.571^2*1 = 0.32653 W
p = P1 + P2 + P3 = 2.29 W
c)
E1
P = i V = 0.571*12 = 6.86 W
d)
E2
P = i V = 0.571*8 = -4.57 W
e)
overall rate of production of electrical energy = 6.86 - 4.57 = 2.29
overall rate of consumption of electrical energy in the circuit = i^2*Rnet = 0.571^2*(5+1+1) = 2.29
SAME