Here you pull downward on the rope that is attached to the cylinder, which fits

Question

Here you pull downward on the rope that is attached to the cylinder, which fits tightly on the rod. Also, as the cylinder descends, it pulls on a block via a second rope, and the block slides over a lab table. Again consider the cylinder Here you pull downward on the rope that is attached to the cylinder, which fits tightly on the rod. Also, as the cylinder descends, it pulls on a block via a second rope, and the block slides over a lab table. Again consider the cylinder-rod-Earth system, similar to that shown in Figure (b) below. Your work on the system is 200 J. The system does work of 60 J on the block. Within the system, the kinetic energy increases by 130 J and the gravitational potential energy decreases by 20 J. What is the change in the thermal energy within the system?

Explanation / Answer

work done on system = work done by system +(change in K.E + change in P.E) + change in thermal energy

200=60+(130+(-20)) +chnage in T.E

change in T.E =30J

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