In a carnival ride, passengers stand with their backs against the wall of a cyli
ID: 2261889 • Letter: I
Question
In a carnival ride, passengers stand with their backs against the wall of a cylinder. The cylinder is set into rotation and the floor is lowered away from the passengers, but they remain stuck against the wall of the cylinder. For a cylinder with a 2.0-m radius, what is the minimum speed that the passengers can have for this to happen if the coefficient of static friction between the passengers and the wall is 0.25? In a carnival ride, passengers stand with their backs against the wall of a cylinder. The cylinder is set into rotation and the floor is lowered away from the passengers, but they remain stuck against the wall of the cylinder. For a cylinder with a 2.0-m radius, what is the minimum speed that the passengers can have for this to happen if the coefficient of static friction between the passengers and the wall is 0.25? In a carnival ride, passengers stand with their backs against the wall of a cylinder. The cylinder is set into rotation and the floor is lowered away from the passengers, but they remain stuck against the wall of the cylinder. For a cylinder with a 2.0-m radius, what is the minimum speed that the passengers can have for this to happen if the coefficient of static friction between the passengers and the wall is 0.25?Explanation / Answer
Vertical forces are mg and frictional force
for not to fall mg should be equal to frictional force
so mg = umv^2/r
so 9.8 = 0.25*v^2/2
so v= 8.85 m/s