Part A What must the charge (sign and magnitude) of a particle of mass 1.41 g be
ID: 2272199 • Letter: P
Question
Part A What must the charge (sign and magnitude) of a particle of mass 1.41g be for it to remain stationary when placed in a downward-directed electric field of magnitude600N/C ? Use 9.81m/s2 for the magnitude of the acceleration due to gravity.Part B What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67 Part A What must the charge (sign and magnitude) of a particle of mass 1.41g be for it to remain stationary when placed in a downward-directed electric field of magnitude600N/C ? Use 9.81m/s2 for the magnitude of the acceleration due to gravity.
Part B What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67 Part B What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67
Explanation / Answer
A) sign should be negative because weight is acting in downward direction so electrical force should act upwards and since field is in downward direction so charge has to be negative.
qE=-mg
q=-mg/E=-1.41*10^-3*9.81/600=-2.303*10^-5
B)E=mg/q=1.67*10^-27*9.8/1.6*10^-19=1.023*10^-7.