A horizontal wire of length 0.50 m, carrying a current of 6.7 A, is placed in a

Question

A horizontal wire of length 0.50 m, carrying a current of 6.7 A, is placed in a uniform external magnetic field. When the wire is horizontal, it experiences no magnetic force. When the wire is tilted upward at an angle of 19

A horizontal wire of length 0.50 m, carrying a current of 6.7 A, is placed in a uniform external magnetic field. When the wire is horizontal, it experiences no magnetic force. When the wire is tilted upward at an angle of 19 degree it experiences a magnetic force of 4.10 times 10-3 N. Determine the magnitude of the external magnetic field.

Explanation / Answer

A current carrying wire in a magnetic field experiences a force given by

F = i l B sin(angle between direction of current and magnetic field)

Here i=current =6.7A , l=length of wire =0.50m , B=magnetic field

substituting; 4.10 10^-3 = 6.7*0.50*sin19*B

Hence calculate B = 0.00375 tesla The unit for B is Tesla

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---