Hey here is screen shot of the lab instructions just want to make sure we are on
ID: 2287325 • Letter: H
Question
Hey here is screen shot of the lab instructions just want to make sure we are on the same page: I may have calculated wrong, I used the linear motion calculations.
Can any one help out with this physics lab? I have to predict the distance of projection using this information:
initial launch traveled an average distance of 1.128 meters the time I figured out using t=sqrt2d/g t=0.479
and the average velocity is V= 4.701 m/s = sqrt(2*1.129*9.8)
the ramps initial height was 14 cm from where the marble was relased and projected from a table that is 74 cm tall.
I have to predict the distance it will travel when I elevate the ramp to 16cm on a table that is 74 cm tall a total of (90 cm or 0.9 meters).
I'm a little confused on the kinematic equations needed for this calculations.
Explanation / Answer
well, the information shows that
the operater has used formulaes
s = ut + 1/2at^2
and
v^2 = u^2 + 2as
with value of u = 0 which means initial velocity is zero
this can only be possible if the object is being dropped from a certain hight.
which not a projectile motion instead it is a linear uniformly accelerated motion
the statement
"the ramps initial height was 14 cm from where the marble was relased and projected from a table that is 74 cm tall."
doesn't make any connection with the vertical distance 1.129 m
untill we come to a conclusion that is the object has been thrown upward from the ramp with an initial velocity let v0 such that it's vel. at top of the hight is zero and it covers a distance of [ 112.8 - ( 74 + 14 ) ] /2 = 12.4 cm
so the vel with which the object is being projected upward is
v^2 = u^2 - 2as
0 = v0^2 - 2*9.8*12.4
v0 = 15.5897 m/s
now for your statement
"I have to predict the distance it will travel when I elevate the ramp to 16cm on a table that is 74 cm tall a total of (90 cm or 0.9 meters)."
with same velocity the object is projected again in vertially upward direction to coer a distance of 12.4 cm .
therefore
the distance it will travel is = 12.4*2 + 16+74 = 114.8 cm