Part A: Determine the magnitude of the force on an electron traveling 2.9010 5 m

Question

Part A: Determine the magnitude of the force on an electron traveling 2.90105m/s horizontally to the east in a vertically upward magnetic field of strength 0.27T . Express your answer using two significant figures. Part B: Determine the direction of the force on an electron. upward downward to the east to the west to the north to the south Part A: Determine the magnitude of the force on an electron traveling 2.90105m/s horizontally to the east in a vertically upward magnetic field of strength 0.27T . Express your answer using two significant figures. Part B: Determine the direction of the force on an electron. upward downward to the east to the west to the north to the south

Explanation / Answer

A)F=qVB=1.6*10^-19*2.9*10^5*0.27=1.2528*10^-14N

B)to the south

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