Assume that if the shear stress in steel exceeds about 4.00 108 N/m2, the steel

Question

Assume that if the shear stress in steel exceeds about 4.00 108 N/m2, the steel ruptures. (a) Determine the shearing force necessary to shear a steel bolt 1.45 cm in diameter. (b) Determine the shearing force necessary to punch a 1.05-cm-diameter hole in a steel plate 0.800 cm thick.

a) We know that force F is equal to the surface area A times stress ? so we have

F = ?A = ? ? 108 N/m2
Your response differs from the correct answer by more than 10%. Double check your calculations. ? 10?2 m 2 = ? 104 N.

Explanation / Answer

(a) force, F=sigma *A=4*10^8*(pi*(d/2)^2)=4*10^8*(pi*(0.0145/2)^2) =66051 N

(b) force, F=4*10^8*(pi*d*t)=4*10^8*(pi*0.0105*0.008)=105557.51 N

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