Please type the answer clearly with formulas. Thx A) The mass slides on a fricti
ID: 2303655 • Letter: P
Question
Please type the answer clearly with formulas. Thx
A) The mass slides on a frictionless horizontal surface and then encounters a spring with a spring constant of 2000 N/m. The spring stops the sliding block. what is the maximum compression of spring?
B) Now suppose that the block and the hill have a coefficient of kinetic friction of 0.25 (the horizontal surface is a still frictionless). Now, what is the maximum compression of spring?
3. A 2.0kg block slides down a frictionless 30 degree incline from a height of h-2.0m a) The mass slides on a frictionless horizontal surface and then 309Explanation / Answer
A) Potential energy of the block at top = kinetic energy at bottom
mgh = 0.5mv^2
v = sqrt(2gh)
= sqrt(2*9.8*2) = 6.2 m/s
This kinetic energy gets converted to spring potential energy
0.5mv^2 = 0.5kx^2
2*6.2^2 = 2000*x^2
x = 0.195 m
= 19.5 cm
B) if there is friction
Potential energy at top - energy lost due to friciton = Kinetic energy
mgh - umg cos a * d = 0.5mv^2
9.8*2 - 0.25*9.8*cos 30*(2/sin 30) = 0.5*v^2
v = 4.714 m/s
0.5mv^2 = 0.5kx^2
2*4.714^2 = 2000*x^2
x = 0.15 m
= 15 cm