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Please help (7%) Problem 12: In open heart surgery, a small amount of energy is

ID: 2304336 • Letter: P

Question

Please help (7%) Problem 12: In open heart surgery, a small amount of energy is often used to defibrillate the heart. 50% Part (a) 50% Part (b) what voltage, n kilovolts, is applied to the 9.5 F capacitor of a heart defibrillator that stores 39.5 J of energy? Find the amount of stored charge, in millicoulombs. Grade Summas Deductions Potential sinO tan7 8 9 cosO cotanO asinO acoso atanO acotan sinh0 coshO tanO cotanhO O Degrees Radians Submissions Attempts remai (0% per attemp detailed view OME 0 vo BACKS CLEAR Submit Hint Feedback I give up!

Explanation / Answer

As capacitance, C=9.5*10^-6 F

Energy, E=39.5 j

We know that energy stored in capacitor

E =1/2 CV²

Put values

39.5=1/2 *9.5*10^-6 *V²

V²=39.5*2*10^6/9.5 =8.31*10^6

V =2.88*10³ v or V =2.88 Kv.

We also know that E =1/2*QV

Where Q=charge

Put values in

We get

39.5=1/2*Q *2.88*10³

Q=39.5*2*10—³/2.88

Q=27.43*10—³ C 27.43 millicoulombs.