Mass of the wood block used 0240 k mass placed total mass on thetotal ormal forc
ID: 2304341 • Letter: M
Question
Mass of the wood block used 0240 k mass placed total mass on thetotal ormal force CN on the block friction board kg) sE) mass to keep block force to keep block moving uniformly (Ikg) moving uniformly 0.0890 0.140 0.190 0.240 0.290 0.340 0.390 (3-s.f) (kg) 0.100 0.300 0.500 0.700 .900 1.100 1.300 (a). From the data table above, plot the values of the normal forces on the x-axis and frictional forces on the yaks Draw the best fitting line on the graph. Selecting two appropriate points, compute the coefficient of the kinetic friction between the two surfaces. (Show your work) (b). Perform a linear regression analysis for the data pairs ( n, f). Show the regression equation in the formExplanation / Answer
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Problem2: Solution
horizontal force required is F=(static friction)mg
=0.43*85*9.8
=358.19N
Thus, Horizontal force is required to get the crate moving= 358.19 N
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