Problem 46 (4 points extra credit) Consider the following v vs. t graph of the s
ID: 2305966 • Letter: P
Question
Problem 46 (4 points extra credit) Consider the following v vs. t graph of the spring box oscillator v[m/s] 2 4 6 8 10 12 si (a) (1 point) Period T of oscillations of is egual to: (A) T = 2 (D) T = 12 s (B) T = 4s (E) T = (4te)s (C)T=8s (F) T = (8T) S (N) None of the above. (b) (1 point) Maximum speed Vmax of the oscillator is equal to: (A) VMAX = 2 m/s (E) Vmax = (Tc/4) m/s (B) VMAx = 4 m/s (F) VMAX = (2/tt) m/s (C) Vmax = 8 m/s (G) VMAX = (4/Tt) m/s (D) Vmax = (1/2) m/s (H) VMAX = (8/1) m/s (N) None of the above.Explanation / Answer
a) Time period of oscillation means the time required to complete a full cycle or a complete oscillation. So it is 8 secs.Notice that 0 to 2sec is only a half cycle.
b) Maximum speed is 2 m/sec. As the projection of the graph on V axis touches 2 m/sec at its maximum height.